To calculate the solubility of potassium bromide (KBr) at 23 degrees Celsius, we can use the information provided about how its solubility increases with temperature. First, we need to know the solubility of KBr at a reference temperature, which in this case we will consider to be 20 degrees Celsius.
Let’s say the solubility of KBr at 20 degrees Celsius is ‘S’ grams per 100 mL of water. The hint indicates that the solubility increases equally for each degree temperature increase up to 30 degrees Celsius. Thus, we can calculate the increase in solubility for the temperature change from 20 to 23 degrees Celsius.
The increase in temperature is 3 degrees Celsius. If we denote the increase in solubility per degree as ‘x’ grams, then for a 3-degree increase, the total increase in solubility will be 3x grams.
Therefore, the solubility of KBr at 23 degrees Celsius can be calculated as:
Solubility at 23°C = S + 3x
To find the specific values for ‘S’ and ‘x’, we would typically refer to a solubility table or experimental data. However, in the absence of such data, the formula above provides a general approach for calculating the solubility based on the given hints.