Calculate the Molar Mass of Zn(C2H3O2)2

To calculate the molar mass of zinc acetate, which is represented by the chemical formula Zn(C₂H₃O₂)₂, we need to follow these steps:

1. **Identify the atomic masses** – We will use the atomic masses from the periodic table:

• Zinc (Zn) – approximately 65.38 g/mol
• Carbon (C) – approximately 12.01 g/mol
• Hydrogen (H) – approximately 1.01 g/mol
• Oxygen (O) – approximately 16.00 g/mol

2. **Break down the formula** – In Zn(C₂H₃O₂)₂, we have:

• 1 Zinc atom: 1 x 65.38 g/mol = 65.38 g/mol
• 2 Acetate ions (C₂H₃O₂):
• For one acetate ion (C₂H₃O₂):
• 2 Carbon atoms: 2 x 12.01 g/mol = 24.02 g/mol
• 3 Hydrogen atoms: 3 x 1.01 g/mol = 3.03 g/mol
• 2 Oxygen atoms: 2 x 16.00 g/mol = 32.00 g/mol
• Total for one acetate: 24.02 + 3.03 + 32.00 = 59.05 g/mol
• Total for two acetate ions: 2 x 59.05 g/mol = 118.10 g/mol

3. **Add it all together** – Finally, add the mass contributions from zinc and the acetate ions:

65.38 g/mol (Zn) + 118.10 g/mol (2 C₂H₃O₂) = 183.48 g/mol

Thus, the molar mass of Zn(C₂H₃O₂)₂ is approximately 183.48 g/mol.