To calculate the molar mass of lead(II) sulfate (PbSO4), we need to sum the molar masses of all the atoms present in the compound.
1. **Identify the elements in PbSO4**:
- Lead (Pb)
- Sulfur (S)
- Oxygen (O)
2. **Find the molar masses of each element**:
- Molar mass of Lead (Pb) = 207.2 g/mol
- Molar mass of Sulfur (S) = 32.07 g/mol
- Molar mass of Oxygen (O) = 16.00 g/mol
3. **Count the number of atoms for each element in the formula**:
- Lead: 1 atom
- Sulfur: 1 atom
- Oxygen: 4 atoms
4. **Calculate the total molar mass**:
Now we can apply the formula:
Molar mass of PbSO4 = (1 × Molar mass of Pb) + (1 × Molar mass of S) + (4 × Molar mass of O)
Plugging in the values:
Molar mass of PbSO4 = (1 × 207.2) + (1 × 32.07) + (4 × 16.00)
= 207.2 + 32.07 + 64.00
= 303.27 g/mol
Therefore, the molar mass of lead(II) sulfate (PbSO4) is 303.27 g/mol.