A circle has its center at (2, 3) and a radius of 3 units. What is the equation of the circle?

The equation of a circle in the Cartesian coordinate system can be written using the formula:

(x – h)² + (y – k)² = r²

In this formula:

  • (h, k) is the center of the circle.
  • r is the radius of the circle.

In your case, the center of the circle is given as (2, 3) and the radius is 3 units. Plugging these values into the formula, we have:

  • h = 2
  • k = 3
  • r = 3

Substituting these values into the equation results in:

(x – 2)² + (y – 3)² = 3²

which simplifies to:

(x – 2)² + (y – 3)² = 9

So, the equation of the circle with center at (2, 3) and radius of 3 units is:

(x – 2)² + (y – 3)² = 9

More Related Questions