How to Solve a Quadratic Equation x² + 10x + 24 by Completing the Square

To solve the quadratic equation x² + 10x + 24 = 0 by completing the square, follow these steps: Move the constant term to the other side: Start by rearranging the equation: x² + 10x = -24 Complete the square: To complete the square, we need to add the square of half the coefficient of […]

How do you simplify 1 tan2x 1 tan2x?

To simplify the expression 1 tan2x 1 tan2x, we need to clarify it first. It looks like there may be a small formatting issue. It seems you’re asking about the simplification of 1 + tan²(x). Using the Pythagorean identity from trigonometry, we know that 1 + tan²(x) = sec²(x). This identity arises because: tan(x) is […]

What is the antiderivative of e^(2x)?

The antiderivative of e^(2x) can be found using the concept of integration. The function e^(2x) is an exponential function, and when integrating exponential functions, we typically apply the formula for the antiderivative of e^(kx), where k is a constant. In this case, k = 2. The general formula for the antiderivative is: ∫ e^(kx) dx […]

What is the value of the range of the function f(x) = x² – 2?

The function f(x) = x² – 2 is a quadratic function, which means its graph is a parabola. The general form of a quadratic function is f(x) = ax² + bx + c, where ‘a’, ‘b’, and ‘c’ are constants. In this case, ‘a’ is equal to 1 (which is positive), indicating that the parabola […]

Solve for x: 5x + 10 = 30 – 15x

To solve the equation 5x + 10 = 30 – 15x, we need to isolate the variable x. First, let’s get all the x terms on one side of the equation and the constant terms on the other side. We can do this by adding 15x to both sides: 5x + 15x + 10 = […]

How do you simplify the expression 2 divided by (2 + 5i)?

To simplify the expression 2 / (2 + 5i), we can multiply both the numerator and the denominator by the conjugate of the denominator. The conjugate of a complex number a + bi is a – bi. In this case, the conjugate of 2 + 5i is 2 – 5i. So, let’s rewrite the expression: […]