How to Solve the Equation 2x² + 3x – 7 + x² + 5x – 39 for x?

To solve the equation 2x² + 3x – 7 + x² + 5x – 39 = 0, we first need to combine like terms.

Start by combining the terms:

  • 2x² + x² = 3x²

Next, combine the x terms:

  • 3x + 5x = 8x

Now, combine the constant terms:

  • -7 – 39 = -46

Putting it all together, our equation simplifies to:

3x² + 8x – 46 = 0

Next, we can use the quadratic formula to find the solutions for x, which is given by:

x = (-b ± √(b² – 4ac)) / 2a

In our equation, the coefficients are:

  • a = 3
  • b = 8
  • c = -46

Now plug these values into the quadratic formula:

  • b² – 4ac = 8² – 4 * 3 * (-46) = 64 + 552 = 616

Now we can calculate x:

  • x = (−8 ± √616) / (2 * 3)
  • x = (−8 ± 24.8) / 6

This gives us two potential solutions:

  • x = (16.8) / 6 = 2.8
  • x = (−32.8) / 6 = -5.467

Thus, the two solutions for the equation are:

  • x = 2.8
  • x ≈ -5.467

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