What is the axis of symmetry for f(x) = 2x² + 4x + 5?

The axis of symmetry for a quadratic function in the standard form f(x) = ax² + bx + c can be found using the formula:

x = -b / (2a)

In this case, the coefficients are:

  • a = 2
  • b = 4
  • c = 5

Plugging in the values of a and b into the formula gives us:

x = -4 / (2 * 2) = -4 / 4 = -1

Thus, the axis of symmetry for the quadratic function f(x) = 2x² + 4x + 5 is x = -1.

This means that the parabola opens upwards and is symmetrical around the vertical line x = -1. Any point on one side of this line has a corresponding point on the other side, making it a key feature in the graph of the function.

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