How many solutions does this linear system have: y = x + 2 and 6x – 4y = 10?

To determine how many solutions this linear system has, we can solve the equations.

The first equation is:

y = x + 2

Now, we can substitute this expression for y into the second equation:

6x – 4(x + 2) = 10

Expanding this gives:

6x – 4x – 8 = 10

Combining like terms:

2x – 8 = 10

Now, we add 8 to both sides:

2x = 18

Dividing both sides by 2:

x = 9

Now substituting back to find y:

y = 9 + 2 = 11

This gives us a single solution: (9, 11).

Since we found one unique solution, we can conclude that this linear system has exactly one solution.

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