Which point is an x-intercept of the quadratic function f(x) = x^2 – 8x + 9?

To find the x-intercepts of the quadratic function, we need to set the function equal to zero and solve for x.

The function given is:

f(x) = x^2 - 8x + 9

Setting f(x) to zero:

0 = x^2 - 8x + 9

This is a standard form of a quadratic equation. To solve for x, we can either factor it or use the quadratic formula. In this case, let’s try factoring.

We need two numbers that multiply to +9 and add to -8. The numbers -1 and -9 fit this:

(x - 1)(x - 9) = 0

Setting each factor equal to zero gives us:

x - 1 = 0  or  x - 9 = 0

Thus, the solutions are:

x = 1  or  x = 9

This means the x-intercepts of the function are the points (1, 0) and (9, 0) on the Cartesian plane.

So, the x-intercepts of the function f(x) = x^2 – 8x + 9 are the points (1, 0) and (9, 0).