What are the first ten terms of a sequence whose first term is 10 and whose common difference is 2?

The first ten terms of the sequence can be found by starting with the first term and repeatedly adding the common difference. In this case, the first term is 10, and the common difference is 2. We can calculate the terms as follows:

1. 1st term: 10
2. 2nd term: 10 + 2 = 12
3. 3rd term: 12 + 2 = 14
4. 4th term: 14 + 2 = 16
5. 5th term: 16 + 2 = 18
6. 6th term: 18 + 2 = 20
7. 7th term: 20 + 2 = 22
8. 8th term: 22 + 2 = 24
9. 9th term: 24 + 2 = 26
10. 10th term: 26 + 2 = 28

Therefore, the first ten terms of the sequence are: 10, 12, 14, 16, 18, 20, 22, 24, 26, 28.