What is the equation of a circle with a center at (1, 4) and a point on the circle at (4, 8)?

To find the equation of a circle, we can use the standard form of a circle’s equation, which is given by:

(x – h)² + (y – k)² = r²

In this equation, (h, k) is the center of the circle and r is the radius. In our case, the center is given as (1, 4), so h = 1 and k = 4.

Next, we need to determine the radius ‘r’. The radius is the distance from the center of the circle to any point on the circle. We know that there is a point on the circle at (4, 8). We can find the radius using the distance formula:

r = √((x₂ – x₁)² + (y₂ – y₁)²)

Here, (x₁, y₁) is (1, 4) and (x₂, y₂) is (4, 8). Plugging in the values, we get:

r = √((4 – 1)² + (8 – 4)²)

r = √(3² + 4²)

r = √(9 + 16)

r = √25

r = 5

Now that we have the radius, we can substitute the values into the circle’s equation:

(x – 1)² + (y – 4)² = 5²

So, the equation of the circle becomes:

(x – 1)² + (y – 4)² = 25

This is the equation of the circle with a center at (1, 4) that passes through the point (4, 8).

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