To find the cost of each box, let’s denote the cost price of the first box as C1 and the second box as C2. According to the problem, we know:
- C1 + C2 = 1300
Additionally, Ramesh sold one box at a profit of 20% and another at a loss of 12%. The selling prices (SP) can be expressed as:
- SP of the first box = C1 + 0.20 * C1 = 1.20 * C1
- SP of the second box = C2 – 0.12 * C2 = 0.88 * C2
Since the selling prices are the same, we can set them equal to each other:
1.20 * C1 = 0.88 * C2
Now we have two equations:
- C1 + C2 = 1300
- 1.20 * C1 = 0.88 * C2
From the first equation, we can express C2 in terms of C1:
C2 = 1300 – C1
Now, substitute this expression for C2 into our second equation:
1.20 * C1 = 0.88 * (1300 – C1)
Distributing the 0.88 gives:
1.20 * C1 = 1144 – 0.88 * C1
Now, add 0.88 * C1 to both sides:
1.20 * C1 + 0.88 * C1 = 1144
2.08 * C1 = 1144
Now, divide both sides by 2.08:
C1 = 1144 / 2.08 = 550
Now that we have C1, we can find C2:
C2 = 1300 – 550 = 750
Thus, the cost of the first box is Rs 550 and the cost of the second box is Rs 750.