To calculate the probability of tossing three ones in a row with a six-sided die, we first need to understand that each die has six sides, numbered from 1 to 6. When the die is tossed once, the chance of landing on any specific number (like one) is 1 out of 6, or mathematically, P(1) = 1/6.
Now, since we are tossing the die three times, the events are independent. This means the outcome of one toss does not affect the others. Therefore, to find the probability of rolling three ones in a row, we can multiply the probabilities of each individual event:
P(Three ones) = P(1 on first toss) × P(1 on second toss) × P(1 on third toss)
P(Three ones) = (1/6) × (1/6) × (1/6) = 1/216
Thus, the probability of observing three ones in a row when tossing a six-sided die three times is 1/216.