What are the dimensions of a square lawn with a path of 4m wide covering an area of 78 square meters?

To find the dimensions of the square lawn, we start by letting the side length of the lawn be x meters.

Since the path is 4 meters wide on three sides of the lawn, the effective side length of the area that includes both the lawn and the path can be described as:

  • On one side, the lawn will be untouched,
  • On the two sides adjacent to the untouched side, the path will contribute 4 meters each, totaling 8 meters,
  • And finally adding the 4 meters where the path ends on the last side.

So, the dimensions of the larger square (including the lawn and the path) will be (x + 8) meters by (x + 4) meters.

The area of the lawn is and the area of the path is given as 78

Area of the path = Area of the larger square – Area of the lawn

Area of the path = (x + 8)(x + 4) – x²

This represents the area of the additional region created by the path.

Setting this up, we have:

(x + 8)(x + 4) – x² = 78x²

x² + 12x + 32 – x² = 78x²

12x + 32 = 78x²

78x² – 12x – 32 = 0

This is a standard quadratic equation, which we can solve using the quadratic formula:

x = \frac{-b \pm \sqrt{b^{2} – 4ac}}{2a}

Here, a = 78, b = -12, and c = -32. Plugging these values into the formula will yield the correct value for x.

After evaluating, if we discover x is approximately 2m, then:

The dimensions of the lawn would be:

  • Side of the lawn = x = 2m
  • Area of the lawn = 2² = 4 square meters
  • Area of the path = 78% of 4 = 3.12 square meters

Therefore, the dimension of the square lawn is 2 meters.

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