What is the slope of the line tangent to the graph of y = ln(2x) at the point where x = 4?

To find the slope of the line tangent to the graph of y = ln(2x) at the point where x = 4, we first need to calculate the derivative of the function with respect to x.

The derivative of y = ln(2x) can be found using the chain rule. The derivative is:

dy/dx = (1/2x) * (d(2x)/dx) = (1/2x) * 2 = 1/x

Now that we have the derivative, we can find the slope at the specific point where x = 4:

dy/dx = 1/4

Therefore, the slope of the tangent line to the graph of y = ln(2x) at the point where x = 4 is 1/4.