What is the perimeter of PQR with vertices P(2, 9), Q(7, 3), and R(2, 3) in the coordinate plane?

To find the perimeter of triangle PQR with the given vertices, we first need to calculate the lengths of all three sides: PQ, QR, and RP.

1. **Calculating PQ:**
Using the distance formula, which is given by d = √((x2 – x1)² + (y2 – y1)²), we plug in the coordinates of P(2, 9) and Q(7, 3):

PQ = √((7 – 2)² + (3 – 9)²)
= √(5² + (-6)²)
= √(25 + 36)
= √61

2. **Calculating QR:**
Now, we calculate the distance between Q(7, 3) and R(2, 3):

QR = √((2 – 7)² + (3 – 3)²)
= √((-5)² + 0²)
= √25
= 5

3. **Calculating RP:**
Finally, we find the distance between R(2, 3) and P(2, 9):

RP = √((2 – 2)² + (9 – 3)²)
= √(0² + 6²)
= √36
= 6

4. **Calculating the Perimeter:**
Now, we sum the lengths of all sides to get the perimeter:

Perimeter = PQ + QR + RP
= √61 + 5 + 6
= √61 + 11

Thus, the perimeter of triangle PQR is approximately 22.81 units when you calculate √61.

More Related Questions