Find the values of x for which the series converges x 3n2n

To determine the values of x for which the series converges, we first express the series explicitly. The given series can be interpreted as:

S = ∑ (x * 3^n * 2^n)

This can be rewritten as:

S = x * ∑ (3 * 2)^n

Now, simplify the series term:

S = x * ∑ (6^n)

We recognize that the series ∑ (6^n) is a geometric series with a common ratio of 6. A geometric series converges when the absolute value of the common ratio is less than 1:

|6| < 1

Since this condition is never satisfied for real numbers, the series diverges for all values of x.

Therefore, there are no values of x for which the series converges.

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