On which of the following intervals is the function f(x) = 4 cos(2x) decreasing?

To determine where the function f(x) = 4 cos(2x) is decreasing, we first need to find the derivative of the function. The key to understanding the behavior of the function lies in its derivative.

The derivative of f(x) is given by:

f'(x) = -8 sin(2x)

To find where the function is decreasing, we need to set the derivative less than zero:

-8 sin(2x) < 0

This simplifies to:

sin(2x) > 0

The sine function is positive in the intervals where the angle is in the first and second quadrants. For sin(θ) > 0, we have:

0 < 2x < π or π < 2x < 2π

Dividing these inequalities by 2 gives us the intervals:

0 < x < π/2 and π/2 < x < π

Thus, the intervals on which the function f(x) = 4 cos(2x) is decreasing are:

  • nπ < x < nπ + π/2
  • nπ + π/2 < x < (n+1)π

where n is any integer. You can check specific intervals based on this condition to see whether the function is indeed decreasing.

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