How do you find an equation of the line having the given slope and containing the given point m = 8, y = 4, x = 5?

To find the equation of a line given the slope (m) and a point on the line (x, y), you can use the point-slope form of a linear equation, which is:

y – y₁ = m(x – x₁),

where (x₁, y₁) is the given point and m is the slope.

In your case, the slope m = 8 and the point is (5, 4). We can substitute these values into the formula:

y – 4 = 8(x – 5)

Now, let’s simplify this equation:

y – 4 = 8x – 40

Next, add 4 to both sides:

y = 8x – 36

This is the equation of the line in slope-intercept form (y = mx + b), where the slope is 8 and the y-intercept is -36.

Thus, the equation of the line with slope 8 that passes through the point (5, 4) is y = 8x – 36.