To find the equation of the line that passes through the points (6, 3) and (4, 9), we start by determining the slope of the line using the formula:
m = (y2 – y1) / (x2 – x1)
Here, we can let (x1, y1) be (6, 3) and (x2, y2) be (4, 9). Substituting the values:
m = (9 – 3) / (4 – 6) = 6 / -2 = -3
Now that we have the slope (m = -3), we can use the point-slope form of the equation of a line, which is given by:
y – y1 = m(x – x1)
Substituting (x1, y1) = (6, 3) and m = -3 into the equation:
y – 3 = -3(x – 6)
Expanding this gives us:
y – 3 = -3x + 18
Rearranging to put it in slope-intercept form (y = mx + b):
y = -3x + 21
Therefore, the equation of the line that passes through the points (6, 3) and (4, 9) is:
y = -3x + 21