What is the solution to the system of equations 2x + 4y = 12 and y = x + 3?

To solve the system of equations, we will use the substitution method. The equations given are:

1. 2x + 4y = 12
2. y = x + 3

First, we can substitute the expression for y from the second equation into the first equation. This means wherever we see y in the first equation, we will replace it with (x + 3):

2x + 4(x + 3) = 12

Now, we distribute the 4 in the equation:

2x + 4x + 12 = 12

Combine like terms:

6x + 12 = 12

Next, we will isolate 6x by subtracting 12 from both sides:

6x = 0

Now, we divide both sides by 6:

x = 0

Now that we have the value for x, we can find the value for y by substituting x back into the second equation:

y = x + 3

y = 0 + 3

y = 3

So, the solution to the system of equations is:

x = 0 and y = 3.