What is the equation of the line in slope intercept form that passes through (4, 2) and (2, 3)?

To find the equation of the line in slope-intercept form (y = mx + b), we first need to calculate the slope (m) using the two points given: (4, 2) and (2, 3).

The slope formula is:

m = (y2 – y1) / (x2 – x1)

Plugging in our points:

m = (3 – 2) / (2 – 4) = 1 / -2 = -1/2

Now that we have the slope, we can use one of the points to find the y-intercept (b). Let’s use the point (4, 2).

Using the slope-intercept form:

y = mx + b

We can substitute in the slope and the coordinates of the point:

2 = (-1/2)(4) + b

2 = -2 + b

Now, we solve for b:

b = 2 + 2 = 4

Now we have both the slope and the y-intercept. We can write the equation of the line:

y = -1/2x + 4

So, the equation of the line in slope-intercept form that passes through the points (4, 2) and (2, 3) is:

y = -1/2x + 4

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