What is the sum of the arithmetic series from 5 to n 1 sigma 3n 2?

To find the sum of the arithmetic series from 5 to n represented by the sigma notation, we first need to clarify what the series looks like. The expression you’ve provided suggests an arithmetic series where each term increases by a common difference.

Let’s denote the series. The series from 5 up to n can be expressed as:

  • 5, 6, 7, …, n

To find the sum of this series, we can use the formula for the sum of an arithmetic series:

S = (n/2) * (first term + last term)

Where:

  • S is the sum of the series
  • n is the number of terms
  • first term is 5
  • last term is n

Now, to find n, the number of terms in the series:

Number of terms = (last term – first term) + 1 = (n – 5) + 1 = n – 4

Now, substituting into the sum formula:

S = ((n – 4)/2) * (5 + n)

This gives us the sum of the arithmetic series from 5 to n.

Therefore, the sum of the arithmetic series from 5 to n is:

S = rac{(n – 4)(5 + n)}{2}

In summary, to calculate the sum, substitute the value of n in the formula, and you’ll get the answer based on the limits of your series.

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