To find the equations for which both x = 5 and x = -5 are solutions, we need to understand that both values need to satisfy the same equation.
One way to form such an equation is to use the fact that if x = 5 and x = -5 are roots, the factors of the equation can be represented as:
- (x – 5)
- (x + 5)
This leads us to the equation:
(x – 5)(x + 5) = 0
Expanding this gives:
x2 – 25 = 0
This shows that any equation that can be derived from (x – 5)(x + 5) = 0 or equivalent forms will have both x = 5 and x = -5 as solutions. Therefore, equations like:
- x2 – 25 = 0
- 2x2 – 50 = 0 (scaled version)
- x2 + 10x – 15 = 0 (if roots are modified accordingly)
will also be valid. It’s critical that both solutions satisfy the same polynomial equation for them to be classified as solutions of that equation.