What is the third term of a sequence that has a first term of 3 and a common ratio of 3?

To find the third term of a geometric sequence, we can use the formula for the nth term of a geometric sequence, which is:

an = a1 × r(n-1)

Where:

  • an is the nth term of the sequence.
  • a1 is the first term of the sequence.
  • r is the common ratio.
  • n is the term number.

In this case, the first term a1 is 3 and the common ratio r is also 3. We are looking for the third term, so we set n = 3.

Now we can substitute the values into the formula:

a3 = 3 × 3(3-1)

Calculating this step by step:

  1. a3 = 3 × 32
  2. a3 = 3 × 9
  3. a3 = 27

Therefore, the third term of the sequence is 27.

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