What are the dimensions of a rectangle if the length is 97cm more than 4 times the width and the perimeter is 914cm?

Let the width of the rectangle be represented as w. According to the problem, the length l can be expressed as:

l = 4w + 97

The perimeter P of a rectangle can be calculated using the formula:

P = 2(l + w)

Substituting the given perimeter value:

914 = 2(l + w)

We can simplify this equation to:

457 = l + w

Now, substituting the expression for length in terms of width into this equation:

457 = (4w + 97) + w

Combine like terms:

457 = 5w + 97

Next, isolate w by subtracting 97 from both sides:

457 – 97 = 5w

360 = 5w

Now, divide both sides by 5:

w = 72

Having determined the width, we can find the length:

l = 4(72) + 97 = 288 + 97 = 385

Thus, the dimensions of the rectangle are:

  • Width: 72 cm
  • Length: 385 cm

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