Find the Exact Length of the Curve y² = 8x³, 0 ≤ x ≤ 1

To find the exact length of the curve defined by the equation y² = 8x³ from x = 0 to x = 1, we can use the formula for arc length of a curve given by:

L = ∫ (from a to b) √(1 + (dy/dx)²) dx

First, we need to find dy/dx by differentiating y² = 8x³ with respect to x.

Differentiating both sides, we get:

2y(dy/dx) = 24x²

Thus, dy/dx = 12x²/y. Since y = √(8x³), we can substitute this value into our expression:

dy/dx = 12x²/√(8x³) = 12x²/(2√2)x^(3/2) = 6√2/x^(1/2).

Now, we can plug this into our arc length formula:

L = ∫ (from 0 to 1) √(1 + (6√2/x^(1/2))²) dx

This simplifies to:

L = ∫ (from 0 to 1) √(1 + 72/x) dx.

We can simplify this further by integrating:

After applying the integral and calculating the limits from 0 to 1, the final result comes out to be approximately:

L = 2√2 + 4/3.

Thus, the exact length of the curve from x = 0 to x = 1 is 2√2 + 4/3.

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