When x = 3 and y = 5, by how much does the value of 3x^2 + 2y exceed the value of 2x^2 + 3y?

To find out by how much the value of 3x² + 2y exceeds 2x² + 3y, we first need to substitute the values of x and y into these expressions.

Given that x = 3 and y = 5:

First, we calculate 3x² + 2y:
3(3²) + 2(5) = 3(9) + 10 = 27 + 10 = 37.

Now, we will calculate 2x² + 3y:
2(3²) + 3(5) = 2(9) + 15 = 18 + 15 = 33.

Now that we have both values, we find the difference:

37 (value of 3x² + 2y) – 33 (value of 2x² + 3y) = 4.

So, the value of 3x² + 2y exceeds the value of 2x² + 3y by 4.