What is the y-intercept of the quadratic function f(x) = x^2 – 6x + 12?

The y-intercept of a function is the point where the graph of the function intersects the y-axis. This occurs when the value of x is zero.

To find the y-intercept of the quadratic function f(x) = x^2 – 6x + 12, we substitute x with 0:

f(0) = (0)^2 - 6(0) + 12

Simplifying this gives us:

f(0) = 0 - 0 + 12 = 12

Therefore, the y-intercept is the point (0, 12). This means when x is 0, the value of the function f(x) is 12, which tells us that the graph of the quadratic function crosses the y-axis at the point (0, 12).