If f(x) = 16x + 30 and g(x) = 14x + 6, for which value of x does f(g(x)) = 0?

To solve for the value of x such that f(g(x)) = 0, we first need to find g(x) and then substitute it into f(x).

Given:

  • f(x) = 16x + 30
  • g(x) = 14x + 6

Now, we can find f(g(x)). First, we need to substitute g(x) into f(x):

f(g(x)) = f(14x + 6)

Now, replace x in f(x):

f(14x + 6) = 16(14x + 6) + 30

Distributing the 16:

f(14x + 6) = 224x + 96 + 30

Combining like terms:

f(14x + 6) = 224x + 126

Now set f(g(x)) equal to 0:

224x + 126 = 0

To isolate x, first subtract 126 from both sides:

224x = -126

Now divide both sides by 224:

x = -126 / 224

Simplifying this fraction gives:

x = -63 / 112

Thus, the value of x for which f(g(x)) = 0 is -63 / 112.

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