What is the equation of the line in slope-intercept form containing the points (6, 1) and (3, 2)?

To find the equation of the line in slope-intercept form (y = mx + b), we need to determine the slope (m) and the y-intercept (b). First, we calculate the slope using the formula:

m = (y2 – y1) / (x2 – x1)

Plugging in the given points (6, 1) and (3, 2), where (x1, y1) = (6, 1) and (x2, y2) = (3, 2):

m = (2 – 1) / (3 – 6) = 1 / -3 = -1/3

Now that we have the slope, we can use one of the points to find the y-intercept (b). We’ll use the point (6, 1):

y = mx + b

1 = (-1/3)(6) + b

1 = -2 + b

b = 1 + 2 = 3

Now that we have both the slope and the y-intercept, the equation of the line in slope-intercept form is:

y = -1/3x + 3

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