For what value of x is sin x cos 19 where 0 < x < 90?

To solve the equation sin x = cos 19, we can use the identity that relates sine and cosine:

sin x = cos (90 – x). This means we can set up the equation:

cos (90 – x) = cos 19

From the properties of cosine, we know that if cos A = cos B, then:

  • A = B + 360n or
  • A = -B + 360n (where n is any integer)

In our case, since we’re dealing with degrees and x must be between 0 and 90 degrees, we only need to consider the first option.

So:

90 – x = 19

Solving for x gives:

x = 90 – 19
x = 71

Therefore, the value of x that satisfies the equation sin x = cos 19 for 0 < x < 90 is x = 71 degrees.

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