What is the equation of the line that passes through (4, 1) and (2, 3)?

To find the equation of the line that passes through the points (4, 1) and (2, 3), we can follow these steps:

  1. Calculate the slope (m): The slope formula is given by:
  2. m = (y2 – y1) / (x2 – x1)

    Plugging in our points (x1, y1) = (4, 1) and (x2, y2) = (2, 3):

    m = (3 – 1) / (2 – 4) = 2 / -2 = -1

  3. Use the point-slope form to find the equation: The point-slope form is:
  4. y – y1 = m(x – x1)

    Using the point (4, 1) and the slope we found (m = -1):

    y – 1 = -1(x – 4)

    Expanding this:

    y – 1 = -x + 4

    y = -x + 5

Thus, the equation of the line that passes through the points (4, 1) and (2, 3) is:

y = -x + 5

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