Find the slope of the function which is the slope of the tangent line to the graph of the function y = x² + 2x + 3 at the point x = 1

To find the slope of the tangent line to the function y = x² + 2x + 3 at the point x = 1, we first need to calculate the derivative of the function. The derivative represents the slope of the tangent line at any given point.

We start by differentiating the function:

y' = d/dx (x² + 2x + 3) = 2x + 2

Now, we will evaluate the derivative at x = 1:

y'(1) = 2(1) + 2 = 2 + 2 = 4

Thus, the slope of the tangent line to the graph of the function at the point where x = 1 is 4.