What is the linear factorization of the function f(x) = x^4 – 16x^2?

To factor the function f(x) = x^4 – 16x^2, we can start by recognizing that this expression is a polynomial. The first step is to factor out the common term.

Notice that we can factor out x^2 from the expression:

f(x) = x^2(x^2 – 16)

The term (x^2 – 16) is a difference of squares, which can be factored further:

x^2 – 16 = (x – 4)(x + 4)

So, substituting this back into our expression gives:

f(x) = x^2(x – 4)(x + 4)

This is the factorization into linear factors.

Therefore, the complete linear factorization of the function f(x) = x^4 – 16x^2 is:

f(x) = x^2(x – 4)(x + 4)

The final answer consists of one quadratic factor, x^2, and two linear factors, (x – 4) and (x + 4).

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