What is the equation of the line in slope intercept form that passes through (3, 1) and (1, 5)?

To find the equation of the line in slope-intercept form (y = mx + b), we first need to determine the slope (m) and the y-intercept (b) of the line that passes through the two given points.

The two points are (3, 1) and (1, 5). We can calculate the slope using the formula:

m = (y2 – y1) / (x2 – x1)

Here, (x1, y1) = (3, 1) and (x2, y2) = (1, 5).

Plugging in the values, we get:

m = (5 – 1) / (1 – 3) = 4 / -2 = -2

Now that we have the slope, we can use one of the points to find the y-intercept (b). Let’s use the point (3, 1).

We can plug in the values into the slope-intercept equation:

y = mx + b

Selecting point (3, 1):

1 = -2(3) + b

Now we simplify:

1 = -6 + b

Adding 6 to both sides gives:

b = 7

Now we have both the slope and the y-intercept. Thus, the equation of the line in slope-intercept form is:

y = -2x + 7

More Related Questions