What is the equation of a circle whose center is at the origin and whose radius is 16?

The equation of a circle centered at the origin (0, 0) can be expressed using the formula:

  • (x – h)² + (y – k)² = r²

In this formula, (h, k) represents the coordinates of the center of the circle, and r represents the radius. Since the center of our circle is at the origin, we have:

  • h = 0
  • k = 0
  • r = 16

Substituting these values into the equation gives us:

  • (x – 0)² + (y – 0)² = 16²
  • Which simplifies to:
  • x² + y² = 256

Therefore, the equation of the circle whose center is at the origin and whose radius is 16 is:

  • x² + y² = 256

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