What is the remainder when 2x³ + 4x² + 32x + 18 is divided by x – 3?

To find the remainder of the polynomial 2x³ + 4x² + 32x + 18 when divided by x – 3, we can use the Remainder Theorem. This theorem states that the remainder of a polynomial f(x) when divided by x – a is simply f(a).

In this case, a = 3. So, we will evaluate the polynomial at x = 3.

Let’s calculate:

  • f(3) = 2(3)³ + 4(3)² + 32(3) + 18
  • = 2(27) + 4(9) + 32(3) + 18
  • = 54 + 36 + 96 + 18
  • = 204

Thus, the remainder when 2x³ + 4x² + 32x + 18 is divided by x – 3 is 204.

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