To find the value of b² – 4ac for the quadratic equation 5x² + 7x + 6, we first need to identify the coefficients a, b, and c from the standard form of a quadratic equation, which is ax² + bx + c.
In this equation:
- a = 5
- b = 7
- c = 6
Now we can calculate b² – 4ac:
First, we find b²:
b² = 7² = 49
Next, we calculate 4ac:
4ac = 4 * 5 * 6 = 120
Now we substitute these values into the expression b² – 4ac:
b² – 4ac = 49 – 120 = -71
Therefore, the value of b² – 4ac for the equation 5x² + 7x + 6 is -71.