To find the equation of a line that passes through a specific point and has a given slope, we can use the point-slope form of a line’s equation. The point-slope form is expressed as:
y – y1 = m(x – x1)
Here, (x1, y1) is the point the line passes through, and m is the slope.
In our case, the point is (2, 12) so we can substitute x1 = 2 and y1 = 12. The slope, m, is given as 3. Plugging these values into the equation gives us:
y - 12 = 3(x - 2)
Now, let’s simplify this equation:
y - 12 = 3x - 6
y = 3x - 6 + 12
y = 3x + 6
Thus, the equation of the line that passes through the point (2, 12) and has a slope of 3 is:
y = 3x + 6