Find the possible value or values of y in the quadratic equation 4y^2 + 4y = 0

To solve the quadratic equation 4y² + 4y = 0, we can start by factoring:

First, we can factor out the common term, which is 4y

4y(y + 1) = 0

Now, we have a product of two factors equal to zero. According to the zero product property, at least one of the factors must be equal to zero for the equation to hold. This leads us to two possible equations:

  1. 4y = 0
  2. y + 1 = 0

Solving the first equation 4y = 0 gives:

y = 0

Solving the second equation y + 1 = 0 gives:

y = -1

Thus, the possible values of y that satisfy the equation are:

  • y = 0
  • y = -1

In conclusion, the solutions to the quadratic equation 4y² + 4y = 0 are y = 0 and y = -1.

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