What substitution should be used to rewrite 4x^12 + 5x^6 + 14 = 0 as a quadratic equation?

To rewrite the equation 4x12 + 5x6 + 14 = 0 as a quadratic equation, we can use a substitution method that simplifies the terms. A suitable substitution in this case is to let y = x6.

Using this substitution, we can express the equation in terms of y:

  • Since x12 = (x6)2 = y2, we can rewrite 4x12 as 4y2.
  • 5x6 will simply become 5y.

Thus, the equation transforms to:

4y2 + 5y + 14 = 0

This is now a standard quadratic equation in the variable y. By substituting y = x6 back after solving for y, we can find the values for x.

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