What is the equation of a circle with center (3, 3) and radius 2?

The equation of a circle can be expressed in the standard form: (x – h)² + (y – k)² = r², where (h, k) is the center of the circle, and r is the radius.

Given the center of the circle at (3, 3) and a radius of 2, we can substitute these values into the equation:

  • h = 3
  • k = 3
  • r = 2

Plugging these into the formula gives:

(x – 3)² + (y – 3)² = 2²

This simplifies to:

(x – 3)² + (y – 3)² = 4

So, the equation of the circle with center (3, 3) and radius 2 is (x – 3)² + (y – 3)² = 4.

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