Find the Quotient of 2x^4 + 3x^3 + 6x^2 + 11x + 8 ÷ (x + 2)

To find the quotient when dividing the polynomial 2x4 + 3x3 + 6x2 + 11x + 8 by (x + 2), we can use polynomial long division.

1. **Set up the division:** Write 2x4 + 3x3 + 6x2 + 11x + 8 under the long division symbol and (x + 2) outside.

2. **Divide the first term:** Divide the leading term of the dividend (2x4) by the leading term of the divisor (x). This gives us 2x3.

3. **Multiply and subtract:** Multiply 2x3 by (x + 2) which gives 2x4 + 4x3. Subtract this from the original polynomial:

  • 2x4 + 3x3 + 6x2 + 11x + 8
  • -(2x4 + 4x3)
  • ———————————–
  • -x3 + 6x2 + 11x + 8

4. **Repeat the process:** Next, repeat the division process. Divide -x3 by x to get -x2. Multiply and subtract again:

  • -x3 + 6x2 + 11x + 8
  • – (-x3 – 2x2)
  • ———————————–
  • 8x2 + 11x + 8

5. **Continue until all terms are processed:** Keep dividing, multiplying, and subtracting. After fully processing, we get:

The final quotient is: 2x3 – x2 + 4 and a remainder which can be represented as:

Remainder = (R)/(x + 2) where R is the value left after division.

This method helps break down complex polynomials into simpler parts, making it easier to understand how they relate to one another through division.

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