How to Find the Number of Units x That Produces the Minimum Average Cost per Unit c in the Equation c = 0.001x³ + 5x + 250?

To minimize the average cost per unit c, we first start with the given equation for total cost:

c = 0.001x3 + 5x + 250

The average cost per unit (AC) is calculated by dividing the total cost by the number of units produced:

AC = c/x = (0.001x3 + 5x + 250)/x = 0.001x2 + 5 + 250/x

To find the value of x that minimizes the average cost, we need to differentiate this average cost function with respect to x and set the derivative to zero:

d(AC)/dx = 0.002x – 250/x2

Setting the derivative equal to zero gives:

0.002x – 250/x2 = 0

Rearranging the equation leads to:

0.002x3 = 250

Now, solve for x:

x3 = 250 / 0.002

x3 = 125000

Taking the cube root of both sides, we find:

x = 50

Thus, the number of units x that produces the minimum average cost per unit is 50 units.

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