Factor Completely: 3x² + 5x + 1 + 3x + 1 + 3x + 5 + x + 1 + 3x + 5 + x + 1 (Prime)

To factor the expression completely, we first need to simplify it by combining like terms. Let’s break it down step by step.

The original expression is:

3x² + 5x + 1 + 3x + 1 + 3x + 5 + x + 1 + 3x + 5 + x + 1.

Now, let’s combine the terms:

  • Combine the x² terms: 3x² (only one term).
  • Combine the x terms: 5x + 3x + 3x + x + 3x = 15x.
  • Combine the constant terms: 1 + 1 + 5 + 1 + 5 + 1 = 14.

So we can rewrite the expression as:

3x² + 15x + 14.

Now we will factor this quadratic expression. We look for two numbers that multiply to 3 * 14 = 42 and add to 15. The numbers that work are 6 and 7.

Now we can rewrite the middle term:

3x² + 6x + 7x + 14.

Next, we can group the terms:

  • (3x² + 6x) + (7x + 14).

Factor out the common factors in each group:

  • 3x(x + 2) + 7(x + 2).

Notice that (x + 2) is a common factor. Factor it out:

(x + 2)(3x + 7).

Since both factors (x + 2) and (3x + 7) don’t have any further common factors, we have the completely factored form:

(x + 2)(3x + 7).

Finally, check if the expression can be factored further:

Both factors are not factorable over the integers, meaning they are prime in this context.

Thus, the completely factored form of the original expression is:

(x + 2)(3x + 7).

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