What is the solution to the system of linear equations 6x + 7y = 59 and 4x + 5y = 41?

To solve the system of linear equations given by 6x + 7y = 59 and 4x + 5y = 41, we can use the method of substitution or elimination. Here, we’ll use the elimination method.

First, we’ll align the equations for clarity:

1) 6x + 7y = 59

2) 4x + 5y = 41

We can multiply the second equation by 1.5 to make the coefficient of x in both equations similar:

3) 1.5 * (4x + 5y) = 1.5 * 41

Which simplifies to:

3) 6x + 7.5y = 61.5

Now we have:

  • 6x + 7y = 59
  • 6x + 7.5y = 61.5

Next, we subtract the first equation from the modified second equation:

(6x + 7.5y) – (6x + 7y) = 61.5 – 59

This results in:

0.5y = 2.5

Solving for y, we divide both sides by 0.5:

y = 2.5 / 0.5 = 5

Now that we have y, we substitute this value back into one of the original equations to find x. We can use the first equation:

6x + 7(5) = 59

This simplifies to:

6x + 35 = 59

Subtracting 35 from both sides gives us:

6x = 24

Dividing both sides by 6 yields:

x = 4

Thus, the solution to the system of equations is:

x = 4 and y = 5.

In conclusion, the values of x and y satisfy both equations, confirming they are the correct solution.

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