To solve the quadratic equation x² – 24x + 80 by completing the square, we follow these steps:
- Move the constant to the other side: Start with the original equation:
- x² – 24x = -80
- Complete the square: Take the coefficient of x, which is -24, divide by 2 to get -12, and then square it to get 144:
- Add and subtract 144: This means:
- x² – 24x + 144 = 144 – 80
- Rearranging gives us:
- (x – 12)² = 64
Next, we take the square root of both sides:
- x – 12 = ±8
This results in two equations:
- x – 12 = 8 → x = 20
- x – 12 = -8 → x = 4
Thus, the solution set of the equation is:
- x = 20
- x = 4
In conclusion, the solution set of the equation x² – 24x + 80 = 0 is {4, 20}.