If x² – 6x + 8 = 0, then x = 4 or x = 2: True or False?

This statement is True.

To verify, we can factor the quadratic equation x² – 6x + 8. We are looking for two numbers that multiply to 8 (the constant term) and add up to -6 (the coefficient of x).

The numbers -2 and -4 work because:

  • -2 * -4 = 8
  • -2 + -4 = -6

Thus, we can factor the equation as:

(x – 2)(x – 4) = 0

Setting each factor equal to zero gives:

  • x – 2 = 0 → x = 2
  • x – 4 = 0 → x = 4

So the solutions to the equation are indeed x = 2 and x = 4. Therefore, the statement is true.

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