Prove that sin(πx) sin(x)

To prove that sin(πx) sin(x) is equal to a certain expression, we can use the product-to-sum identities in trigonometry.

The product-to-sum identities state that:

  • sin(a) sin(b) = (1/2) [cos(a-b) – cos(a+b)]

In our case, let a = πx and b = x. Then we can rewrite the expression:

sin(πx) sin(x) = (1/2) [cos(πx – x) – cos(πx + x)]

Now, simplify the arguments of the cosine functions:

  • πx – x = (π – 1)x
  • πx + x = (π + 1)x

This gives us:

sin(πx) sin(x) = (1/2) [cos((π – 1)x) – cos((π + 1)x)]

Thus, we have proved that:

sin(πx) sin(x) = (1/2) [cos((π – 1)x) – cos((π + 1)x)]

This shows the relationship between the product of the sine functions and the sum of cosines.

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